Thu 11 Jun 2009
Can a vacuum become a conductor? OR The physics of electron flow
Posted by sciencegeekgirl under Science Explanations[13] Comments
Here was an interesting discussion on a science teacher’s listserv, which came down to the question — can a vacuum become a conductor? What is it that we really need in order for charge to flow between two points? What is the physics of electron flow? The physics teacher in question wrote:
The Paul Hewitt book has a test question that reads: In order for charge to flow from one place to another, there must be a
A. Potential difference between the two places.
B. Conductor, such as a wire, connecting the two places.
C. both A and B.
D. none of these.The book’s answer is C (both A and B). I’m wondering why A isn’t the answer. In the case of the van de Graff or lightening you create a potential difference between two locations (say me and the van de Graff) and the charge will eventually flow … I guess the air acts as the conductor from van de Graff to me? But is there a situation where there is enough of a potential difference between to places and charge doesn’t flow? Would the van de Graff not work in a vacuum?
A veteran physics teacher (Al Sefl, who always knows more physics than moi) responded:
The key to the Hewlett question is that it asks about charge flow. Current cannot flow through an insulator until the point of breakdown is reached. If you have a sphere X with a positive charge and a sphere Y with a negative charge there will be no flow between them until a conductor connects them. Before that conductor is there, there will be lines of electrostatic force but no flow. If the potential were great enough the air would break down to become a conductor and you would have flow. So, C is the correct answer, you must have a potential difference AND a conductor to conduct the charges.
Yes, a Van de Graaff generator will work in a vacuum. High voltage capacitors used in broadcast transmitters and radar units are vacuum capacitors where the charge is stored between two plates surrounded by an evacuated space. The electrostatic lines of force do not need air to exist.
That’s all fine and dandy, but most of the people on the listserv didn’t understand that second paragraph (and neither did I), not knowing enough about broadcast transmitters and such. A teacher asked, do you mean that the Van de Graaff will store charge in a vacuum, but not throw off sparks? After all, what would the charge be flowing through if the Van de Graaff is in a vacuum? There’s no air to ionize (or “break down”).
Al responded with a clarification:
A vacuum may also be a conductor. The old cathode ray tube of years past sends a beam of electrons from a gun through a high vacuum to impact the phosphor screen. So, when the potential becomes high enough current will flow through a vacuum. In a CRT it does get an assist from thermionic emission in the gun.
The miniature lightning bolts we see from a Van de Graaff are really the paths of broken down insulator air that has become conductive and ionized. You would not see that in a vacuum. If you put a sharp point on the negative terminal then the charge concentration will push off electrons that will travel to the positive terminal. The vacuum will become a conductor.
So, C is still the correct answer. If charges FLOW they must do so through a conductor. ANYTHING will become a conductor if the electrostatic charge exceeds its dielectric. If electrons are flowing through something it *is* a conductor.
Perhaps where the Hewlett presentation becomes unclear is the definition of what a conductor is. Most of us immediately think of a piece of copper wire *but* it can be anything if the potential is high enough.
So, a vacuum can become a conductor, even though there’s nothing to ionize (and thus you won’t see the glow from the electrons as they travel through a vacuum, as you do in the air). But by definition, if charge is flowing, it’s flowing through a conductor! Paul Doherty explained that when there is an electric field that is large enough (it has to be very very large), then it will produce electron/positron pairs in the vacuum. Those electrons and positrons are what flow to conduct electric current.
On a side note — the charged particles given off by the Sun aren’t visible as they pass through the vacuum of space… but they are visible when they hit our magnetosphere as the aurora borealis.
And another teacher offered a clarifying comment:
I was taught to get over the idea of being protected by an insulator. We were told that an insulator is a bad conductor. My trade teacher felt that insulator was a weak word and preferred to talk about everything being a conductor, just good conductors (copper) or bad conductors (glass).
So, the discussion got interestingly esoteric here. The original questioner then posited:
If any space can be considered a conductor given a high enough potential difference, then I think the answer to Hewett’s question should be we just need a potential difference to get a flow of charge. After all, he didn’t explicitly state that we need to have charged particles, which I think would be necessary to have a flow of charge. So why state that an omnipresent conductor is necessary?
Also, if a vacuum has charged particles moving through it, is it still a vacuum?
Paul Doherty emphasized that the correct answer to the question is still “C.” You can have a potential difference and no flow of charge, because the voltage may not be low enough to create its own conductor out of the insulator between the two places. With enough potential difference an insulator is turned into a conductor, but you STILL need both a potential difference and a conductor for charge to flow.
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13 Responses to “Can a vacuum become a conductor? OR The physics of electron flow”
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Chris Goedde
Posted: Jun 11th, 2009 at 12:54 pm1Reply to this comment.Consider the photo-electric effect, where you shine light on a metal and (if the light has a short enough wavelength), electrons will be ejected from the metal. In that case, you get charge flow between two points without a potential difference between those points (in fact, the charge can flow against a potential difference) and without a conductor. So I would argue that the correct answer is really D.
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Assaf
Posted: Jun 11th, 2009 at 6:18 pm2Reply to this comment.All this lawyer-speak makes me dizzy
. Every person reading the original question will interpret ‘conductor’ slightly differently, and the answer will depend on the interpretation. Chris, I’m not an expert on light-matter interaction but I’d bet there is a “potential” difference involved as well. The electrons are ejected from the metal due to the atom-photon-lattice interaction. The photons themselves constitute an electromagnetic field, which is basically a potential difference (albeit in a time-dependent framework there is also a vector potential involved).
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Assaf
Posted: Jun 11th, 2009 at 9:41 pm4Reply to this comment.Oddly enough when you tear the electron out of its orbit you’re moving it against the nucleus’s potential (i.e. from low to high potential) – that is, opposite the direction you’d envision current in (in a typical circuit electrons flow from high to low potentials). It’s “anti current”!
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Stich
Posted: Jun 12th, 2009 at 3:59 pm6Reply to this comment.As I understand it, electron flow through conductors is more of a bumping of electrons from atom to atom in the conductor medium. In the case of say copper wiring, they bump very nicely and readily, so it is a great conductor. In air, there aren’t many atoms near each other, so they have to bump under a lot more amperage (pressure).
A vacuum by definition is devoid of atoms, so no bumping could occur. Instead, a free flow of electrons would have to propagate through the vacuum, and as such it doesn’t make a lot of sense to me to call those electrons “the conductor.” It would more be electron flow without a conductive medium, which would be a very uncommon case of electrical flow and require special conditions. Do electrons really ever like to hang out without some sort of atom to orbit?
Of course you could eject matter and make electrons conduct along the matter stream. That is how a new military plasma weapon system works. A laser creates a straight path of photons, and then high power plasma is injected into the laser path, creating a directed energy flow similar to lightning.
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Ben
Posted: Jun 12th, 2009 at 10:57 pm7Reply to this comment.It is D. Vacuum conduction usually occurs by two mechanisms, “glow discharge” or ballistic carrier transport. Most of the time, vacuum conduction is glow discharge, which is really the ionization of trace gasses in the imperfect vacuum. This occurs when the electric field derivative gets high enough. It’s kind of a funny process in that it occurs most easily at intermediate vacuum levels, typically around 1 Torr. In that range, even a typical 9 volt battery can arc between its electrodes. This is a major design problem in building electronics for operation in vacuo, since it allows components to short out in strange and unexpected ways. In some sense, the trace gases become conductive, but they only remain conductive as long as you keep dumping a sufficient amount of energy into it (called “simmering” in glow discharge lamp jargon). It’s called “glow discharge” because it’s usually accompanied by a glowing arc, so it can be quite useful for making light sources.
Ballistic carrier transport is rarer in nature, but it does happen. In that case, the electron (usually) is ejected out of the cathode and hurries on its merry way over to the anode. There is no conducting medium, just an electron and a lot of nothingness for it to not run into. This mainly occurs in vacuum electronic devices like photomultipliers (the photoelectric effect) or cathode ray tube electron guns (thermionic emission). Ballistic transport can also occur in solids, but that’s a very weird and unusual thing that you usually only see on microscopic scales. I should note that this won’t happen without a potential difference. This ballistic transport mechanism can give rise to charge transport without or against an imposed potential, in which case what you’re actually doing is converting the energy that produced the emission into electrical power.
There’s also another kind of vacuum breakdown that can theoretically occur at very high field strengths, but I don’t know if it’s ever been demonstrated in the lab. Basically, if the field gets intense enough, it can dissociate particle-antiparticle pairs generated in the vacuum.
It’s certainly true that in most practical cases, you need a conductor, but if you make the field strength high enough, those charges are going to find a way to get to each other come hell or high water.
The potential difference is required in order to get charge transport without putting any energy into the system, but if you do put energy into the system, it’s certainly possible to make a current flow without having imposed an electrical potential. Now, you could argue that there’s necessarily a potential difference created when you make a current flow, so there is a chicken and egg issue – you can’t separate charges without a potential difference, and you can’t have an (electrical) potential difference without separated charges.
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Captain Skellett
Posted: Jun 16th, 2009 at 8:37 am8Reply to this comment.Very interesting post! I can’t believe that a vacuum can be a conductor and still a vacuum, but I’m not going to argue!!! Physics, I have found, often does this sort of thing – states something simple, and then has to explain it in a very complex way once you start really thinking about it. It’s a problem with most of the sciences, I think, and probably all things in general.
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Squark
Posted: Jun 16th, 2009 at 12:57 pm9Reply to this comment.Firstly, the electric field strength at which electron-positron pair creation begins is of the order of magnitude of
http://www34.wolframalpha.com/input/?i=(electron+mass)^2+*+(speed+of+light)^3+%2F+(electron+charge+*+Planck%27s+constant)
2.1E17 V/m OUCH!!!
Secondly, even if the electric field is not that strong, a capacitor disconnected from a voltage source will discharge (albeit very slowly). This is because thermal fluctuations will occasionally give an electron enough energy to cross the potential barrier and reach the other electrode.
Thirdly, this will happen even at zero temperature because of quantum tunneling!
It should be fun to compute the current induced by the above two effects.
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Squark
Posted: Jun 16th, 2009 at 2:07 pm10Reply to this comment.Sorry, I was inaccurate. At first, I thought dimensional considerations only are sufficient to given an order of magnitude estimate of the critical electric field strength. However, dimensional considerations are not enough since we can introduce an arbitrary function of the fine structure constant.
Now, all tree level Feynman diagrams for electron-positron emission in a macroscopic external field depend on alpha and E only through the product alpha E. Hence, my previous estimate was in fact an estimate of alpha E. E itself ishttp://www34.wolframalpha.com/input/?i=(electron+mass)^2+*+(speed+of+light)^3+%2F+(electron+charge+*+Planck%27s+constant+*+fine+structure+constant)
2.9E19 V/m
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Tom
Posted: Jun 16th, 2009 at 3:53 pm11Reply to this comment.Paul Doherty’s justification at the end is wrong. The presence of a potential difference is a necessary but insufficient condition for current flow, but the question asks what is necessary, not what is sufficient.
That materials, and even a vacuum, may be considered conductors under certain conditions makes this a trick question, IMO, especially so if this an introductory book/course, as it is drawing on advanced concepts to justify that answer; one must consider the definition of “conductor” presented in the book or course. So one must be prepared to accept a “wrong” answer as being right — it’s not like this is an unknown phenomenon in physics.
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Stich
Posted: Jun 17th, 2009 at 2:35 pm12Reply to this comment.Well put, Tom. That’s what I was getting at.
